[Gate-users] Reflective surface not totally reflecting?

[Jenny Nilsson]

Hello again,
Just wanted to add a comment to my previous explanation.

For a ground-front-painted surface all optical photons undergo Lambertian reflection only. Hence, ground-front-painted describes a diffuse reflector. 

Regards!
Jenny


24 mar 2014 kl. 16:41 skrev Jenny Nilsson <jenny.nilsson at radfys.gu.se>:

> Hello Amy and other Gate users,
> 
> If you have a dielectric-dielectric surface with a polished finish, then optical photons can leave the volume through refraction. Reflectivity = 1 means that no optical photons are absorbed by the surface, but optical photons can still leave if refraction is chosen instead of reflection.
> 
> If you want all optical photons to be reflected then use a dielectric-metal surface with efficiency set to 0. 
> 
> Or
> 
> Use a dielectric-dielectric surface with ground-front-painted or polsihed-front-painted finish
> Ground-front-painted: reflects all optical photons against a rough surface.
> Polsihed-front-painted finish: reflects all optical photons against a polished surface.
> 
> Regards
> Jenny Nilsson
> 
> 
> 
> 24 mar 2014 kl. 14:55 skrev Amy Meldrum <ameldru at g.clemson.edu>:
> 
>> Hello everyone,
>> 
>> I am trying to define a completely reflective surface for a volume (aluminum foil). In my Surfaces.xml file for this surface I set Specular Spike = 1, and Reflectivity = 1. Yet when running a small simulation, it seems that some optical photons tend to end their track in the layer whose surface I had set to be reflective, rather than being reflected off of it and into other volumes in my geometry. Is there something I'm missing in defining the surface?
>> 
>> Thank you,
>> 
>> -Amy
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