[Gate-users] Biasing -> variance reduction technique
Daniel
maierd83 at gmail.com
Mon Nov 12 11:16:15 CET 2018
Hello to all,
I try to understand the 'setSecBiasing' command.
I am simulating an X-ray tube and use
/process/em/setSecBiasing eBrem anode_target 3 100 MeV
for testing with visualization and a small number of particles.
In the visualization I can see that if a bremsstrahlung interaction
occurs three photons are generated:
1363 88 0.268 -0.346 89.3 0.0244 0.00129 0.000384 89.3
anode_target_phys eBrem
1364 :----- List of 2ndaries - #SpawnInStep= 3(Rest= 0,Along= 0,Post=
3), #SpawnTotal= 78 ---------------
1365 : 0.268 -0.346 89.3 0.00589 gamma
1366 : 0.268 -0.346 89.3 0.00785 gamma
1367 : 0.268 -0.346 89.3 0.000462 gamma
1368 :-----------------------------------------------------------------
EndOf2ndaries Info ---------------
1369 89 0.268 -0.346 89.3 0.0241 0.000215 7.4e-05 89.3
anode_target_phys eIoni
1370 90 0.268 -0.346 89.3 0.0228 0.000317 9.4e-05 89.3
anode_target_phys eIoni
1371 :----- List of 2ndaries - #SpawnInStep= 1(Rest= 0,Along= 0,Post=
1), #SpawnTotal= 79 ---------------
1372 : 0.268 -0.346 89.3 0.00107
But I don't understand how they can have different energies because
there is only one electron leaving this interaction (i.e. the
bremsstrahlung is not complete), see attached screenshot.
My questions are the following:
- What is the energy of the outgoing electron and how is it calculated?
- What is a good strategy to find this outgoing electron energy in the
very long list created with 'tracking/verbose 2'? I guessed it is the
one at step 89, but it has 0.0241 MeV energy while the ingoing electron
had 0.0244 MeV (step 88). The energy sum of the outgoing e- and the 3
gammas does not match the ingoing e-.
Thanks in advance,
Daniel
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