[Gate-users] projection images
Rajaram, Ramya (H USA)
ramya.rajaram at siemens.com
Fri Jul 23 00:46:27 CEST 2010
Thank you MJ - I was able to use Matlab to read in the .sin file but see only zeros and ones in it. Why is that? I am using the benchSPECT macro (gate.sin)
Another question: I have root output enabled - I can see the different graphs that the Hits and Singles trees generate but is there a way to arrive at the numbers behind the graphs? For instance, how do we know the position (energy, time, etc) of a certain event at the detector? Is that a fair bit of C++ or other programming, or does root offer ways to do it?
Thank you all for your help and time,
Ramya
-----Original Message-----
From: snuphd at gmail.com [mailto:snuphd at gmail.com] On Behalf Of Park MinJae
Sent: Thursday, July 22, 2010 2:48 PM
To: Rajaram, Ramya (H USA)
Cc: gate-users at lists.opengatecollaboration.org
Subject: Re: [Gate-users] projection images
Dear Ramya,
I usually use "matlab" and "C++" for the post-processing.
If you want to only display, you can use bunch of programs, such as 'mricro'.
Cordially yours,
MJ
//=================================================
// Ph.D. Park MinJae
//
// Johns Hopkins University
// School of Medicine, Dept of Radiology
// Division of Medical Imaging Physics
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// "You see, But you do not Observe" - Sherlock Holmes -
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On Thu, Jul 22, 2010 at 1:51 PM, Rajaram, Ramya (H USA)
<ramya.rajaram at siemens.com> wrote:
> Hi all,
>
> I am new to Gate and am trying to simulate a SPECT system. My question
> is regarding projection images. I have projection output enabled by
> giving:
>
> /gate/output/projection/enable
> /gate/output/projection/setFileName proj1
> /gate/output/projection/pixelSizeX 0.9 mm
> /gate/output/projection/pixelSizeY 0.9 mm
> /gate/output/projection/pixelNumberX 32
> /gate/output/projection/pixelNumberY 32
> /gate/output/projection/projectionPlane YZ
>
> I get two files - a .hdr file and .sin file. How do I view the .sin
> file? Also, how do I actually get the projection images?
>
> I greatly appreciate any help/suggestions.
>
> Thank you,
>
> Ramya
>
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