[gate-users] Image Reconstruction of Gate output

[Kris Thielemans]

> 
> BTW, I was pussled by the sinogram width of DST (420 crystal 
> per ring). The number 249 is larger than the 420/2 = 210. How 
> can DST get the extra LORs of 39? By interpolation? Could 
> this help to improve the spatial resolution? Thank you!
> 
Notation: N= num_detectors per ring

Why do you think that the max sinogram width is N /2? This is a hardware
choice (recent CTI scanners tend to have sinogram_width=N/2). The
'physical' maximum of LORs in 2D sinograms is (N^2-N)/2 (i.e. all lines
between pairs of detectors, excluding the degenerate cases, and
identifying det pairs ij and ji). The max number of views is N/2 (you'd
expect N, but it's halved because of interleaving). So, the max sinogram
width is something like (N-1)


Kris